Solve for X

I put together a couple of equations for you not to actually solve for, but to break out X from. Some are first-degree equations, some are second-degree, and the difficulty varies quite a bit. Remember to post the solutions step by step as it's extremely easy to just cram the equations into an equation solver/breakout otherwise:

[list=1][*]5x(75x+32y)=5xy
[*](x+y)/(y+x)=xy
[*](x-y)/(y-x)=xy
[*]sqrt(5x)=y
[*](x+y)/(x-y)=2xy
[*](1337x)^2-(15y)^2=sqrt(y)[/list=1]

Well, I'm not doing these now, no time, but:

4. x = (y^2)/5

Yeah, that answer is correct, but do post the steps you managed to solve it through.

#4

sqrt(5x)=y

u square both sides to get rid of the sqrt()

u get 5x=y^2

u divide 5 on both sides to isolate x

x=(y^2)/5



#1 (i have a feeling im wrong so plz tell me if i am...if im not ill post step by step)

x=sqrt((-27xy)/375)

4 is right.

I don't know what on earth you did with #1, but here's some basic hints for it:

5x(75x+32y)=5xy
375x^2+160xy-5xy=0
x(375x+155y)=0

So it's a second-degree equation, and one x has to equal 0, but see if you can figure out what the other one equals.

lol...im an idiot...sorry

o well...i tried...although ill work through all of them when i have a chance eventually

1. 15+45=60
2. 60=60

State the reason that makes going from step 1 to step 2 true.

Easy shiz

Number 6!
This one is a bitch...
Had to resolve to paintchat do it right.

Oops, 255 should be 225 isntead, except for that it's all good.

It's the weekend I don't wanna do this.

Too bad... you need the practice... it's to excite the brain.

this is algebra right???

4. sqrt(5x)=y

1. 5x=y/sqrt
2. x= 5y/sqrt

so is the answer THAT or x=y/5xsqrt

??

sqrt is an operation not a variable

sqrt stands for square toor

Ugh, #5 is giving me a headache, I can't crack it.
y=(x-y)(2xy)-x is about as far as I get, and it definitely seems like it's gonna be a fourth-grader, so feel free to help me out with this one a bit.

Bump. Anyone care to give #5 a try?

ill try it but i dont know what ill come up with.

5x(75x+32y)=5xy
375x^2 + 160xy = 5xy
375x^2 = -155xy
375x = -155y
x = -155/375y

(x+y)/(y+x)=xy
(x+y)/(x+y)=xy
1=xy
x=1/y

(x-y)/(y-x)=xy
(x-y)/ -(x-y)=xy
-1=xy
x=-1/y

sqrt(5x)=y
sqrt(5x)^2=y^2
5x=y
x=y/5

(x+y)/(x-y)=2xy
-(y-x)/(x-y)=2xy
-[(y-x)/(x-y)]=2xy
-(-1) = 2xy
x= 1/2y

(1337x)^2-(15y)^2=sqrt(y)
I think your solution to this is correct, so no point in posting

LordZpider:

#1 should have the y in the numerator rather than the denominator. Oh, and the other root is 0.

#2 is correct.

#3 is correct.

#4 is correct.

#5 is incorrect. You can't turn (x+y)/(x-y)=2xy into
-(y-x)/(x-y)=2xy, trying to break out -1 would result in -(-y-x)/(x-y)=2xy.

hmm for number 5 i got

X = 2x^2 y - 2xy^2 - y

yea, for #1 it's hard to write it with one line but it's (-155/375)y

and yes, my #5 is wrong, i have a full load of classes today, and as a matter of fact i'm going to "matrix theory" right now, i did that in sorta a rush (my excuse, obviously), so i'll try to work on it later.

It's sorta embrassing as an engineer to get algebra problems wrong, then again nasa crashed into mars cuz they forgot to convert :-P.

Cheers.