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Posted 2010-07-28, 03:33 PM
in reply to -Spector-'s post "Math (Algebra) Question"
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Okay, I'm no math genius... more like a fucking math retard, but can someone explain this to me?
Ok, why is the degree of a variable with no exponent 1, and the degree of an actual number is 0?
I understand that they have to be those degrees to correctly multiply/divide polynomials, but how exactly did they prove that x = x^1 and 2 = 2^0 (Or any number for that matter...) And any number, to the power of 0 --
-- Ahh, while typing this I think I figured it out. Well, part of it anyway. Correct me if I'm wrong:
Numbers aren't to the power of 0, they have a null power, any number to the power of 0 is 1...
Ok then does Degree = Exponent = Power ?
When stating a degree of a term in a polynomial, if it's a number and it has a degree of 0, it doesn't mean it's to the power of 0, it just means it has no degree?
Wow holy fucking confusing post. My bad guys
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Basically you're stating the power of the variable. 2x^2 has a degree of 2 just the same a 4x^2 and x^2. 2x has a degree of 1 just like 4x and x. Numbers without variables essentially have "x^0" attached to them, since x^0 will always be 1 regardless of x.
So for this equation:
y = 2x^2 + 4x +3
You could rewrite it as:
y = 2x^2 + 4x^1 + 3x^0
Since x^1 = x and x^0=1
The first term has a degree of 2, the second a degree of 1, and the last a degree of 0.
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